Special products and factoring
a(x+y) = ax+ay
(x+y)(x-y) = x2 - y2
(x+y)2 = x2+2xy+y2
(x-y)2 = x2-2xy+y2
(x+a)(x+b) = x2+(a+b)x+ab
(ax+b)(cx+d)=acx2+(bc+ad)x+bd
(x+y)3 = x3+3x2y+3xy2+y3
(x-y)3 = x3-3x2y+3xy2-y3
(x+y)(x2-xy+y2) = x3+y3
(x-y)(x2+xy+y2) = x3-y3
Exercises
Use the special products and factoring equations to solve the following problems by substitution
(2y+2x)
3
(3a+2b)(3a-2b)
(5w-2v)(25w
2+10wv+4v2)
(3z-4t)
3
3(2a-5b)
(2x-3)(2x+3)
(2x-3z)2
(2a+3b)(4a2-6ab+9b2)
(3x+2)(4x+3)
(3x+2y)2
Factoring by Inspection
5bx+7by
25a2-9b2
16a2+24ab+9b2
8a3-27b3
x2-3x-10
Factoring by Grouping
cx-2cy-6dy+3dx
4a2-9x2-6x-1
9x2-6xy+y2-25a2+10ab-b2
(y2+y-9)2-9